解不等式 『x^2-2x』>=1

是绝对值吗？

x^2-2x>=1或x^2-2x<=-1

x^2-2x>=1
x^2-2x-1>=0
x<=2-√2,x>=2+√2

x^2-2x<=-1
(x-1)^2<=0
x=1

所以
x<=2-√2x,x=1,x>=2+√2

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